Optimal. Leaf size=140 \[ -\frac{2 (-2 A n+A+C (3-2 n)) \sin (c+d x) (b \sec (c+d x))^n \text{Hypergeometric2F1}\left (\frac{1}{2},\frac{1}{4} (5-2 n),\frac{1}{4} (9-2 n),\cos ^2(c+d x)\right )}{d (1-2 n) (5-2 n) \sqrt{\sin ^2(c+d x)} \sec ^{\frac{5}{2}}(c+d x)}-\frac{2 C \sin (c+d x) (b \sec (c+d x))^n}{d (1-2 n) \sqrt{\sec (c+d x)}} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.125937, antiderivative size = 140, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 4, integrand size = 33, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.121, Rules used = {20, 4046, 3772, 2643} \[ -\frac{2 (-2 A n+A+C (3-2 n)) \sin (c+d x) (b \sec (c+d x))^n \, _2F_1\left (\frac{1}{2},\frac{1}{4} (5-2 n);\frac{1}{4} (9-2 n);\cos ^2(c+d x)\right )}{d (1-2 n) (5-2 n) \sqrt{\sin ^2(c+d x)} \sec ^{\frac{5}{2}}(c+d x)}-\frac{2 C \sin (c+d x) (b \sec (c+d x))^n}{d (1-2 n) \sqrt{\sec (c+d x)}} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 20
Rule 4046
Rule 3772
Rule 2643
Rubi steps
\begin{align*} \int \frac{(b \sec (c+d x))^n \left (A+C \sec ^2(c+d x)\right )}{\sec ^{\frac{3}{2}}(c+d x)} \, dx &=\left (\sec ^{-n}(c+d x) (b \sec (c+d x))^n\right ) \int \sec ^{-\frac{3}{2}+n}(c+d x) \left (A+C \sec ^2(c+d x)\right ) \, dx\\ &=-\frac{2 C (b \sec (c+d x))^n \sin (c+d x)}{d (1-2 n) \sqrt{\sec (c+d x)}}+\frac{\left (\left (C \left (-\frac{3}{2}+n\right )+A \left (-\frac{1}{2}+n\right )\right ) \sec ^{-n}(c+d x) (b \sec (c+d x))^n\right ) \int \sec ^{-\frac{3}{2}+n}(c+d x) \, dx}{-\frac{1}{2}+n}\\ &=-\frac{2 C (b \sec (c+d x))^n \sin (c+d x)}{d (1-2 n) \sqrt{\sec (c+d x)}}+\frac{\left (\left (C \left (-\frac{3}{2}+n\right )+A \left (-\frac{1}{2}+n\right )\right ) \cos ^{\frac{1}{2}+n}(c+d x) \sqrt{\sec (c+d x)} (b \sec (c+d x))^n\right ) \int \cos ^{\frac{3}{2}-n}(c+d x) \, dx}{-\frac{1}{2}+n}\\ &=-\frac{2 C (b \sec (c+d x))^n \sin (c+d x)}{d (1-2 n) \sqrt{\sec (c+d x)}}-\frac{2 (A (1-2 n)+C (3-2 n)) \, _2F_1\left (\frac{1}{2},\frac{1}{4} (5-2 n);\frac{1}{4} (9-2 n);\cos ^2(c+d x)\right ) (b \sec (c+d x))^n \sin (c+d x)}{d (1-2 n) (5-2 n) \sec ^{\frac{5}{2}}(c+d x) \sqrt{\sin ^2(c+d x)}}\\ \end{align*}
Mathematica [C] time = 2.85872, size = 343, normalized size = 2.45 \[ -\frac{i 2^{n+\frac{1}{2}} e^{-\frac{1}{2} i (4 c+d (2 n+1) x)} \left (\frac{e^{i (c+d x)}}{1+e^{2 i (c+d x)}}\right )^{n+\frac{1}{2}} \left (1+e^{2 i (c+d x)}\right )^{n+\frac{1}{2}} \sec ^{-n-2}(c+d x) \left (A+C \sec ^2(c+d x)\right ) (b \sec (c+d x))^n \left (\frac{e^{\frac{1}{2} i (4 c+d (2 n+1) x)} \left (2 (2 n+5) (A+2 C) \text{Hypergeometric2F1}\left (n+\frac{1}{2},\frac{1}{4} (2 n+1),\frac{1}{4} (2 n+5),-e^{2 i (c+d x)}\right )+A (2 n+1) e^{2 i (c+d x)} \text{Hypergeometric2F1}\left (n+\frac{1}{2},\frac{1}{4} (2 n+5),\frac{1}{4} (2 n+9),-e^{2 i (c+d x)}\right )\right )}{d (2 n+1) (2 n+5)}+\frac{A e^{\frac{1}{2} i d (2 n-3) x} \text{Hypergeometric2F1}\left (n+\frac{1}{2},\frac{1}{4} (2 n-3),\frac{1}{4} (2 n+1),-e^{2 i (c+d x)}\right )}{d (2 n-3)}\right )}{A \cos (2 c+2 d x)+A+2 C} \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
Maple [F] time = 0.222, size = 0, normalized size = 0. \begin{align*} \int{ \left ( b\sec \left ( dx+c \right ) \right ) ^{n} \left ( A+C \left ( \sec \left ( dx+c \right ) \right ) ^{2} \right ) \left ( \sec \left ( dx+c \right ) \right ) ^{-{\frac{3}{2}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (C \sec \left (d x + c\right )^{2} + A\right )} \left (b \sec \left (d x + c\right )\right )^{n}}{\sec \left (d x + c\right )^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (C \sec \left (d x + c\right )^{2} + A\right )} \left (b \sec \left (d x + c\right )\right )^{n}}{\sec \left (d x + c\right )^{\frac{3}{2}}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (b \sec{\left (c + d x \right )}\right )^{n} \left (A + C \sec ^{2}{\left (c + d x \right )}\right )}{\sec ^{\frac{3}{2}}{\left (c + d x \right )}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (C \sec \left (d x + c\right )^{2} + A\right )} \left (b \sec \left (d x + c\right )\right )^{n}}{\sec \left (d x + c\right )^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]